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But without T_hour, cannot find unless assume ratio. - Databee Business Systems

📅 February 27, 2026 👤 scraface

Feb 27, 2026

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\[ C'(t) = \frac{kt^2 + k - 2kt^2}{(t^2 + 1)^2} \]
\[ C'(t) = \frac{-kt^2 + k}{(t^2 + 1)^2} \]
\[ C'(t) = \frac{k(1 - t^2)}{(t^2 + 1)^2} \]
Set \(C'(t) = 0\):
\[ \frac{k(1 - t^2)}{(t^2 + 1)^2} = 0 \]
The numerator must be zero:
\[ 1 - t^2 = 0 \]
\[ t^2 = 1 \]
\[ t = \pm 1 \]
Check the second derivative or evaluate \(C(t)\) at critical points an...

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