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can't fight this feeling - Databee Business Systems

📅 February 26, 2026 👤 scraface

Feb 26, 2026

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🔥 Popular Posts

\boxed{40}
Question: A smart city integrator in San Francisco is analyzing traffi...
Solution: This is a continuous probability problem involving uniform r...
Let each vehicle arrive at a time uniformly distributed over [0,10). W...
Standard technique: Compute the complementary probability — that **no*...
Let $ X_1, X_2, \dots, X_6 \sim \text{Uniform}[0,10] $, and define $ X...
For all six points to lie within some interval of length 2, it is nece...
X_{(6)} - X_{(1)} \leq 2
Because then the earliest and latest arrivals are within 2 minutes, an...
Now, we compute:

📝 Recent Posts

An angel investor is forming advisory panels by selecting 2 biotech sp...
We compute the number of ways to choose 2 specialists from 5 and 2 sci...
\binom{5}{2} = \frac{5!}{2!3!} = \frac{5 \times 4}{2} = 10
\binom{6}{2} = \frac{6!}{2!4!} = \frac{6 \times 5}{2} = 15
\text{Total panels} = 10 \times 15 = 150
So, 150 distinct panels can be formed.
An urban forestry researcher photographs trees in a grid of 4 rows and...
Total number of 1×1 grid positions: \( 4 \times 3 = 12 \).
Number of ways to choose 3 distinct positions: \( \binom{12}{3} = \fra...
Now, favorable outcomes: all 3 positions in different rows.

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