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Home » For Plan A (compounded annually): - Databee Business Systems

For Plan A (compounded annually): - Databee Business Systems

📅 February 27, 2026 👤 scraface

Feb 27, 2026

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📌 P(A) = 0.4, \quad P(B) = 0.5, \quad P(C) = 0.6

📌 We want the probability that **at least two** channels allow sufficient flow, i.e.,

📌 P(\text{at least 2 flows}) = P(A \cap B \cap \overline{C}) + P(A \cap \overline{B} \cap C) + P(\overline{A} \cap B \cap C) + P(A \cap B \cap C)

📌 $ P(A \cap B \cap \overline{C}) = 0.4 \cdot 0.5 \cdot (1 - 0.6) = 0.4 \cdot 0.5 \cdot 0.4 = 0.08 $

📌 $ P(A \cap \overline{B} \cap C) = 0.4 \cdot (1 - 0.5) \cdot 0.6 = 0.4 \cdot 0.5 \cdot 0.6 = 0.12 $

📌 $ P(\overline{A} \cap B \cap C) = (1 - 0.4) \cdot 0.5 \cdot 0.6 = 0.6 \cdot 0.5 \cdot 0.6 = 0.18 $

📌 $ P(A \cap B \cap C) = 0.4 \cdot 0.5 \cdot 0.6 = 0.12 $

📌 Now summing these:

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