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Home » Madden 15: The Secret Strategies You *Must* Know to Win Early! - Databee Business Systems

Madden 15: The Secret Strategies You Must Know to Win Early! - Databee Business Systems

📅 February 27, 2026 👤 scraface

Feb 27, 2026

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📌 A vector $\mathbf{c}$ orthogonal to both $\mathbf{a}$ and $\mathbf{b}$ can be found using the cross product:

📌 \mathbf{c} = \mathbf{a} \times \mathbf{b} = \begin{vmatrix} \mathbf{i} & \mathbf{j} & \mathbf{k} \\ 2 & -3 & 1 \\ 1 & 4 & -2 \end{vmatrix}

📌 Calculate the determinant:

📌 \mathbf{c} = \mathbf{i}((-3)(-2) - (1)(4)) - \mathbf{j}((2)(-2) - (1)(1)) + \mathbf{k}((2)(4) - (-3)(1))

📌 = \mathbf{i}(6 - 4) - \mathbf{j}(-4 - 1) + \mathbf{k}(8 + 3)

📌 = \mathbf{i}(2) + \mathbf{j}(5) + \mathbf{k}(11)

📌 = \begin{pmatrix} 2 \\ 5 \\ 11 \end{pmatrix}

📌 Thus, the vector orthogonal to both $\mathbf{a}$ and $\mathbf{b}$ is:

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Wait — perhaps three consecutive odd integers? But not specified.
Alternatively, maybe the problem meant sum of cubes? Unlikely.
Wait — let's try x = 11: sum = 365
x = 12: 144+169+196=509
No — 425 not achievable.
But 11.87 — so no integer solution.
Perhaps the problem is misstated.
But for the sake of generating, assume a typo and intended sum is 365...
But 434 is closer? 434 vs 425.
Wait — 3(14)^2 + 2 = 3×196 + 2 = 588 + 2 = 590 — too big.

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